xml - How to use XPath to find the closest ancestor in a ancestor-or-self nodelist -

I have a structure with such recursive elements:

  & lt; A & gt; & Lt; P & gt; & Lt; A & gt; & Lt; / A & gt; & Lt; / P & gt; & Lt; A & gt; & Lt; P & gt; & Lt; A & gt; & Lt; C att = "val" /> & Lt; / A & gt; & Lt; / P & gt; & Lt; / A & gt; & Lt; / A & gt;   
 If you are in the form of a C-node, there is $ currentNode, when I use Express  
     
 I get an anonymous list of nodes that match the expression What I need to always get the node to be closest to the tree, in the branches the deepest or highest level.  
 Unfortunately, I could not use XPath 2 max function:  
     
 Note that the closest node is not always above the reference, just above the top ...  
 Any suggestions appreciated!   
 
 
 
 I think you ordered the nodes Get to the former from the parent. Try the  $ currentNode / ancestor-or-self :: a [1]  to get the parent of     c att = "val".