c++ - Is &= guaranteed to behave like hypothetical &&= operator? -

Sometimes I want to do

  bool success = true; Success & amp; = Dosmthing1 (); Success & amp; = Dosmthing2 (); Success & amp; = Dosmthing3 (); If (success)   
 I'm using exceptions that ignores ... My question is that the C ++ standard is guaranteed that  & amp; =  will behave like nonexisting for the case of my use  & amp; Amp; Amp; = Amp;  ...  
 Edit: smthing-s return bool   
 
 
 It depends on you to work  & amp; Amp; = Amp; =  How to expect if you see the  x & amp; Amp; = Y (); If you want to be equal to  x = x & amp; Amp; Y (); , not so, because this expression does not call  y ()  if  x  starts as incorrect, but  x & Amp; ; = Y ();  will be.  
 If you do not expect it to be a short circuit and all your expressions are actually typed in  bool  (do not allow some to be  bool , pointers, Integers, or variables for user-defined objects), it works though it has many restrictions.