pointers - How does dynamically allocating a struct in C work? -

Recently there was an assignment where I had to allocate memory to a structure for dynamic. I used this method:

  myStruct * struct1 = malloc (sizeof * struct1);   
 It just worked fine. However, I do not understand how. I think that the  struct1  indicator has not been started at that point and therefore should not have anything to do with why  malloc (sizeof * struct1) how to assign  Does memory of a valid quantity return?   
 
 
  sizeof  operator does not evaluate operands in C. It looks just like the type, for example:  
  #include & lt; Stdio.h & gt; Int main (zero) {int i = 0; Printf ("% zu \ n", Size I ++); Printf ("% d \ n", i); Return 0; }   
 If you run the above program, you will see that  i  is still 0.  
 Then, in your example,  * structure1  is not evaluated, it is used only for type information.