I have an array int [] com with two values being 0 and 1 (in the initial step )).
I
string [] arr = new string [100]; Element defines another array as
arr element:
arr [0] = {4, 8,10,11,12,14} arr [1] = {1,2,3,4,8,12, 14} .. arr [6] = some I I want to search the int [0] and the int [1] intersection, so I wrote the code in this form:
foreach (int value1 in int intro) {// show logic} Here I should get value 1 as 4,8, but I'm getting 52,44 as value 1.
What am I doing, what's wrong with it?
OK, what are you doing, you do not have any string array that is not an ARRAGE If you do this
arr [0] = "4,8,10,11,12,14"; Advent [1] = "1,2,3,4,8,12,14"; Var intersection = ARR [0]. Cutting (ARR [1]); As a result, you will find this list of characters as arr [0] and arr [1] '4', ',', '8' , '1', '2' which corresponds to the integer values 52 44 56 49 50 , which is actually what you are getting. You have int [,] arr = new int [100,100]; or better list & lt; List & lt; Int & gt; Instead of strings, declare an integer matrix. & Gt; . You can not use an integer like strings, at least not in this context.
list & lt; List & lt; Int & gt; & Gt; Arr = new list & lt; List & lt; Int & gt; & Gt; (); Arr.Add (new list & lt; int & gt; {4,8,10,11,12,14}); Arr.Add (new list & lt; int & gt; {1,2,3,4,8,12,14}); Var intersection = ARR [0]. Cutting (ARR [1]); But if you do not trust me, and want to make sure that you do not have any sense in your previous code, then replace foreach loop and See what's happening:
foreach (punching in cell value 1) {// display logic} In addition, you need to do this Not:
return to zero = convert toInt32 (com [0]. Ostring ()); Int convert a =. ToInt32 (com [1]. Ostring ()); You can change it like something:
int zero = com [0]; Int one = com [1]; But still it is useless because you can:
arr [com] [0]] arr [com [1]]
No comments:
Post a Comment