I have a list Edit: NB will have the highest one Now, what I'm doing is stupid but seems to be effective (I'm wondering if there is a better way ) If I assign all the elements in the Now, I'm pretty sure that this works but (1) it seems incredibly useless and (2) It can not be that I need to run it more often? What is a better way to do this? What you should do: the order in which Your elements are dependent on one another: i.e., Make your list in that order. One Reorder your list for your readability restriction. hx [[i]] Slowly displays this list but the list refers to the "real-world" list. For this reason, the list should be a fixed order (described by the real-world list) in the script for readability. In addition, the list element relies with the exception of the other list elements (
hx [[1]] ) and the dependency is such that some elements depend on the elements given below in the script. For example,
HX [[2]] & lt; - HX [[3]] + 4 HX [[3]] & lt; - HX [[1]] HX [[4]] & Lt; - hx [[2]] - 2
hx [[ii]] in each assignment operation, on the right side
hx [[i]] itself may depend on another
HX [[J]] , but the following kind of thing is never
HX [K]]
hx [[1]] then I run the code typed 150x so that reverse dependency is definitely used. An example below with just 4 list items is
xx
x1 - & gt; X2 ,
x2 - & gt; X3 , and so on.
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