javascript - Typescript call function from base class -

There is a way to call a function from a base call overwritten.

Base Class

  Export Class Base Class {Constructor ({// Asynchronous // some calls started}}   
  Inheritance class   
  Export class InheritanceClass BaseClass extended {initialized () {// meet with base class}}    
 
 
 Do you mean:  
  class base {constructor ( ) {SetTimeout ((=) => {this.initialized ();}, 1000); } Initialized () {console.log ("Base initialized"); }} Class received base {initialized () {console.log ("initialized"); }} Var test: derived = new derivative (); // Console log works well in "initially received" - as expected   
 (focus on weird red graphs on  setTimeout ()  Do not give up, which I think is a bug - it compiles and runs fine.)  
 You need a method present on  base , but you can call it  Can be overridden in the derived  (or in such a way, without calling ) Super Interlaced () ).