linux - bash print first to nth column in a line iteratively -

I am trying to get the column name of a file and am printing it again. I think the problem is with print $ i , but I do not know how to correct it, I'm trying to code:

  #! / Bin / bash for me {2..5} Set snp = head -n 1 small.txt | | Example input file:  
  ID name age gender state extension 1a 12 mt 811 2 esc '{print $ i}' echo $ snp done   
 B12FUT818   
 desired output:  
  name age gender state extension   
 but I found Output is empty screen.   
 
 
 You just would better  read  the first line of your file and result one Archive as an array:  
  Read-A Header & lt;  
  printf "% s \ n" "$ {header   
 and then  printf  related fields: @]: 1 } "  
 In addition, it uses only, and does not contain any unnecessary edges.  
  Edit.  To reply to your comment, you can enable the loop through the header field:  
  read -a header & lt; Small for SNP in "$ {header [@]: 1}" What is "$ snp"   
  Edit 2.  There were many mistakes in its original method, here its the correct version (though I have written a better way to solve your problem before I wrote it):  
  i in {2 .5}; "Snp = $ (head -n 1 small.txt | awk" {print \ $$ i} ")" $ snp "echo   
 
 set < Due to single quotation marks in /  awk '{print $ i}' ,  $ i   
 Code> never gets extended.  
 This algorithm is not good because you are calling  head  and  awk  4 times, while you do not need it to be a single external process.   
 Hope it helps!