I understand that In (Note: this is not mentioned in N3485) 1). Why not I have a general eg. this error returns N3690 7.1.6.4/4 The type of variable declared by auto or delftype (auto) is less than its initiality. This usage is allowed in the namespace area (3.3.6) and in a for-init-statement (6.5.3) while declaring a variable in one block (6.3) . [...] Do I believe that the 2). What would be the harm if such facility was allowed? I am using GCC 4.8.1. Thanks n3690 7.1.6.4/2 The type of placeholder in any reference in any reference, where an announcer is valid, declaration of function declaration in declaration-specifier-seq, type-specifier-seq, conversion-function-id, or trailing-return-type May appear along. 7.1.6.4/3 If a type-specificifier declares one of the declaration-declaration-declaration-declaration-declaration-declaration of a parameter in the declaration of one of the declarations Appears in Lambda is a generic lambda. 7.1.6.4/4 The type of variable declared by automated or deprecated (auto) has been reduced to its initial. The use of variables in blocks (6.3) in the scope of names (3.3.6) and in a for-init-statement (6.5.3), is less used. Auto or Delftip (Auto) will appear in Deed-Excerpt-CEC as a Develop-Specifier, and DeD-Specier-CEC will run with one or more Init-Delighters, each of which will be a blank initial - Iizer. 7.1.6.4/5 The type of a placeholder can also be used to declare a variable in the case of a selection statement (6.4) Or type-id in a new-expression (5.3.4), in a range-declaration, and in a steady declaration, a recurrence statement (6.5) data member who defines a class (9.4. 2) appears within the member-specifications, with the brace-or-equal-initiator. Only such use is cautious. Any other use is prohibited (especially in use in 7.1.6.4/6 This section explicitly permits In any given reference, any program using auto or delta type (auto) in the context has become ill. use of template is a commendable way of overloading but I'm thinking Why was the code to be used for type parameter type> Auto can not be used, so the overloading of the function is being done?
N3690 7.6.1.4/3, that the Lambda expression can be made by providing this example, generic using Auto,
< Code> auto gladda = [] (int i, auto a) {return i; }; // OK: A generic lambda
Function for zero swap (Auto and Parma 1, Delft (Ultimate 1) and Ultimate 2) {decltype (param1) temp = param1; Param1 = param2; Param2 = temp; }
error: the parameter declared Auto .
param1 and
param2 fall into the scope of the block and therefore for auto deduction Are you eligible?
parameter-declaration-clause )
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