python - Extract square-bracketed text from a string -

Does anyone help me strip the characters with strings so that I '[....] For example: a = newyork_74 [mylocation] b = # till the frost characters until you reach the first bracket [c = [mylocation] < P>

Do not consider any nested structures, a method will be used,

  & gt; & Gt; & Gt; Leaving import from Tertol & gt; & Gt; & Gt; B = ''. Joey (drops (lambda c: c! = '[', A])> gt; & Gt; & Gt; B '[mylocation]'   
 use another,  
  & gt; & Gt; & Gt; Import re & gt; & Gt; & Gt; Pat = re.compile (r '\ [. * \]') & Gt; & Gt; & Gt; B = pat.search (a) .group (0)> gt; & Gt; & Gt; B '[mylaw cation]'