It is possible to pass this command line flag like In full debug mode, the C ++ builder also has a -DDEBUG with GCC and then use conditions such as conditions In the
#ifdef DEBUG C ++ Builder 6, there is an underlying assumption of "debug mode" vs "release mode"; Is there a way to go (preferably in a preprocessor) that is being created in the application?
DEBUG conditionally defined Which can be tested with the
#ifdef statement, you can see it present in the conditional list in the conditional list.
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