linux - bash (potentiallly can use perl/python): filter space delimited arg list through regexes -

I have a set of regsets that should be tested in the delimited list in each delimited location.

I want these items to be able to get free space in them which will survive. Therefore: 4 items, abc , def ghi

  ABC DEFT \ ghi jkl abc   
 ,  jkl , and  ABC .  
 If my set of permissions is  
  bk $ ^ g   
 should be output  
  ABC ABC   
 It looks like  grep -f  I can get most of the way from there but to avoid a way to handle the vacant space I just can not do a  tr  from Space to Newline  
 Edit: I think I just wake up to an escape space of regular place for Newlines Uk I can use  sed  for replacement. And  tr  is enough on the way back from new lines if someone has a better idea then by thinking.   
 
 
 I really do not understand how your items are given. / P> 
 It seems that they come from the output of a program  mystery , in a line, like,  
  gniourf @ somewhere $ mystery ABC def You can file (file  myscript ):  
  #! / Bin / bash output = () again = ($ '' ^ '' of 'B' ') "$ {a [@]}" for #re to read your regexes for w; For R for "$ {Re [@]}"; If [[$ w = ~ $ r]]; Then output + = ("$ {w // / \\}") instead of the space with the backslash-space brake fixtures, check "$ {output [@]}"   
 The purpose for which I have made it:  
  #! / Bin / bash # File Mystery Resonance 'abc def \ ghi jkl abc'   
 Then ( Chamom + X Mystery MyScript ):  
  gniourf @here $ ./myster ABC def \ ghi jkl ABC gniourf @ somewhere $ / Mystery | ./mycript ABC ABC   
  Warning  This will break sooner or later, unless  mystery  always outputs decent stuff!