javascript - Passing a function with parameters as parameter of another function -

There are some similar questions, but the one is still confused. Because my case works with the parameter as the second function parameter.

Simple case:

  var that = 'old IE', dowhat = function caller (text, symbol) {} (that + dowet + mikecode);} warning (Text); Func ();}   
 Question:  caller (text, whatsapp (joe, dovat, mikeode))  something to do? I'm not sure if we use unknown functions like  caller (text, function () {...}  (is that unknown function called twice?)  
    
   
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 To pass a function to execute with the argument, you use lambda The lambda parameter is passed as  func .  
 Example: (This  caller  -  text  ,  which is the call to  ,  Dvatt , and  mycode  are parameters / variables. Lambda is still  which ,  dvatt , and  mycode )  
  caller (text, work) (whathappen (joe, davat, mikeode);});   
 "If I understand what you mean, maybe you have seen the syntax."  
  (function () {...}} () ;   
 Which Lambda is said immediately after construction (at the end of launching Lambda Notice the bracket) In the first example, you are creating and passing only anonymous functions (in JavaScript).