bash - variables set in ~/.bashrc and accessing them in shellscript -

I have it at the top. Bashrc, First returning shells for non-interactive

  food = "bar"; Food Drain "Hello World" Export # If the interactive is not running, do not do anything [-S "$ PS1"] & amp; Amp;  
  #! / Bin / bash resonance "a" echo "$ echo"   
 b "  
 I execute test.sh Output:  
  AB   
 2 questions:  
 
 Why do not I see the value of $ FOO?  
 Why do not I see "Hello World"?   
  Edit:  I thought that #! With script / bin / bash, the script triggers a subsealand which will call .bashrc again, am I wrong?  
  Edit:  Even if I call a script from another host, I will not see any value. Even then, will .bashrc be executed?  
  ssh remotehost "/home/username/test.sh"    
 
 
  .bashrc  is automatically available only for non login interactive shells. Often, you will enter  .bashrc  your  .bash_login  Near the beginning of the file, to make sure that  .bashrc  is the source for both login and non-login interactive shells.  
  .bashrc  is not automatically sourced for non-interactive shells, such as when you execute shell scripts start up.  
 Since you export  FOO  to  .bashrc , the fact is that  test.sh  looks  FOO < / Code> Having a null value reveals that you are running the script from the login shell. Does the  buzz echo $  from print  bar ? I would wonder if it did and did not  test.sh .