Suppose you define partial to set positional arguments in an arbitrary order To correct 2 and 3 th arguments you want, the results you want to apply partial to str.split are as follows: (I use but str.rsplit does not use keyword logic, only positional. Partially, how to fix those arguments? The only option is long and wrapper? If you want to define the function inline, then the rapper is ugly, like the function's Defining the argument for the dispute. Lambda is Defacto here, and partial is the second option, but in this case it is lacking. You can not do this with the Can only provide positional logic in partial order. It is mentioned, where they say that Note The conclusion is that On the one hand, in Python 3.3, you can specify and this was also the same issue for many other methods / functions.
Lambda: str.rsplit (S, SEP, 1) #Sep was given.
s.rsplit (... instead of
str.rsplit (s ... and To make more points)
partial (str.rsplit, sep = SEP, maxsplit = 1) # SEP
partial . This is because
The PyArg_ParseTuple function uses the API that does not provide keyword logic from split . From Python's perspective, it seems that the method is defined as Interpretation:
DEF division (self, * Arges): If Len (Arjis) & gt; 2: Increase the type arrow (...) sep = args [0] if the args and none maxsplit = args [1] if LAN (Args)> gt; 1 and -1 ...
partial "is almost equivalent":
def partial (func, * args, ** keywords): def newfunc (* Fargs, ** fkeywords): newkeywords = keywords.copy () newkeywords.update (fkeywords) return func (* (args + fargs), ** newkeywords) newfunc.func = func newfunc.args = args newfunc.keywords = keyword newfunc
return func (* (args + fargs), ** newkeywords) which clearly shows that you
partial Other functions are included in Arguments.
lambda is more powerful than
partial .
maxsplit as a keyword argument:
& gt; & Gt; & Gt; '' Some strings with spaces ''. (Same as 'max', 'some', 'string', 'empty space']
No comments:
Post a Comment