c++ - Enable function depending on template class variables -

I have a simple matrix class that looks like this:

  template & lt ; Int m, int n & gt; Class Matrix {Public: std :: enable_if & lt; Std :: is_same & lt; Matrix, matrix • 4,4 & gt; & Gt; Value, Zero & gt; Translate (float x, float y, float z) {// do stews} private: float mat [m * n]; };   
 I hope that the  std :: enable_if  function will only be available if I have a  matrix and lt; 4,4> gt;  It appears that this is wrong.  
  int main () {matrix <4, 3> Mat3; Mat3.translate (1.0f, 1.0f, 1.0f); Return 0; }   
 The above code is not compiled with any errors What am I doing?  
  I know that I can put just a  static_assert (m == 4 & amp; n == 4)  in the function body, but I'm cleaner I am looking for solution and want to learn something about templates in this process.    
 
 
 For the starter, you should:  
  Typename std :: enable_if & lt; Std :: is_same & lt; Matrix, matrix <4,4> gt; & Gt; :: value, zero & gt; ::   
 Instead of:  
  std :: enable_if  gt; & Gt; :: value, zero & gt;   
 But this will still not work, because this category will be evaluated when the class template is instant, thus an error occurs, even if you ever  translate () .  
 If you can use C ++ 11, you can do the following:  
  template & lt; Typename t = matrix & gt; Typename std :: enable_if & lt; Std :: is_same & lt; T, matrix & lt; 4,4 & gt; :: Price & gt; :: Type translate (float x, float y, float z) {// do stof}   
 here is one. Notice how the compilation error has started by calling  translation ()  from the mere rebound of the notice,  matrix <4,3>  . .