python - Opening a Quickly dialog using a button -

I've created a window using the Quick Add dialog. But I can not understand how to open a dialog with just one button. I have already set a button in my main window and have set the code for it. This is the code for the button:

  def on_quicksitesbutton_clicked (self, widget): dialog = QuicksitesDialog.QuicksitesDialog () result = dialog.run ()   
 I also imported communicate with this line of code:  
  brandsonicweb.QuicksitesDialog import QuicksitesDialog   
 the program runs fine, but when I click on the button on_quicksitesbutton_clicked dialog = file "/home/brandon/brandsonicweb/brandsonicweb/BrandsonicwebWindow.py" in QuicksitesDialog.QuicksitesDialog, line 71 ,:  
  Traceback (most recent call last): I get into terminal () AttributeError: Type Object 'QuicksitesDialog no attribute' QuicksitesDialog '  
 I'm doing wrong? How can I do this work?   
 
 
 or type of function:  
  dialog = QuicksitesDialog ()   
 or the like import:  
  brandsonicweb import QuicksitesDialog  and  
 your code that you finally get it.  
  dialogue = brandsonicweb.QuicksitesDialog.QuicksitesDialog.QuicksitesDialog ()   
 that is a little too much