android - Resources$NotFoundException: resource ID not valid. Why? -

I am trying to add float to my dimens.xml file.

I was reading. When I tried the solution, I got the exception mentioned in the comments. I am trying to understand why why that exception has been thrown away.

Here is the XML for completion:

    
 Here's the code that's going on:  
  last float zoom = this.getResources (). GetDimension (R.dimen.zoom_level);   
 I jumped into the Android source, and here is the method definition for getDimension:  
  get public float (difference ID) throws NotFoundException {synchronize (mTmpValue) )) {Value of the typed value = mTmpValue; GetValue (id, value, true); If (value.type == typed value. TYPE_DIMENSION) {TypedValue.complexToDimension (value.data, mMetrics); } New NotFoundException Throw ("Resource ID # 0x" + Integer.TaxStrin (ID) + "Type # 0x" + Integer. TextString (Value Type) + "Not Valid"); }}   
 So whatever the reason  value.type! = Typed value TYPE_DIMENSION . I do not have my Android source fully set, so I can not easily add the  Log.w ("YARIAN", "value type" + value.type) ' statement.  
 Then I jumped into  getValue  and finds a series of calls:  
  resources.getValue -> AssetManager.getResourceValue - & gt; AssetManager.loadResourceValue   
  loadResourceValue  is an original method and here's where my excavation is different.  
 Does anyone know what is the best way to do what is happening?  
 
 I also noticed that the value typed in a  in  resource . Typpa Floyd  and  typed value. TYPE_DIMENSION . But in XML, I can not write  type = "float" .  
 Use  type = string  for the work described in the comments and then use it to get the float  float.from  is it necessary? Why not and why not?   
 
 
 I know that this is a late reply, but you use it instead of parsing the string Should you have a float like you suggested.  
 XML:  
  & lt; Item name = "float_source" format = "float" type = "raw"> 5.0 & lt; / Item & gt;   
 Java:  
  typed value = new typed value (); Context.getResources (). GetValue (R.raw.float_resource, outside, true); Float float resource = out.get float ();   
 You enter  fraction ,  raw  or  string  as the  type  If you want, then it only matches the resource class in  R .