linux - How do I use the filenames output by "grep" as argument to another program -

I have this grep command which outputs the names of files (in which some patterns Matches), and I want to parse those files with some file-parsing program The pipeline looks like this:

  grep -rl "{some-pattern}" | {Some file-parsing-program} & gt; A.out   
 How do I obtain those files as command line arguments in the file-parsing program? For example, suppose that returns  grep  filenames  a ,  b ,  c . How can I pass file names so that I can  
  {some-file-parse-program} a b c & gt; A.out   
?   
 
 
 It seems to me that you want to:  
  grep - Rl "{some_pattern" | Your command & gt; A.out   
 I'm not sure  a.out  is a good output file name, but we can give that slide. The  xargs  command reads the filenames separated by the white space from the standard input, and then they call  your-command  as those names. It may have to invoke  your-command  many times; Unless you are using GNU  xargs  and you specify  -r ,  your-command  used at least once Even if there is no matching file name Without the use of  
  xargs , you could not use  sed  for this task. Without using  xargs , Pearl (and Python) will be clumsy using the  awk  to 'trivialize' it; It will be easy to type the code to read the file name from standard input and then process each file in return.